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The integral in question is : Vsm(x) I = f dx 1/sin(x) 1/cos(x) Using this substitution: Ir t= 2 - —x dx = —dt You should get: 1/cos(t) I = f N/cas(t) dt Back to x: cos(x) stn(x)21 = f dx laos(x)±sin(x) Hence, = 2 F cst
The integral in question is :
Vsm(x) I = f dx 1/sin(x) 1/cos(x)
Using this substitution:
Ir t= 2 - —x dx = —dt
You should get:
1/cos(t) I = f N/cas(t) dt
Back to x:
cos(x) stn(x)21 = f dx laos(x)±sin(x)
Hence, = 2 F cst
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