Consider the reaction: SO2Cl2(g) <----> SO2(g) + Cl2(g) Kp = 2

Chemistry Jan 12, 2021

Consider the reaction:
SO2Cl2(g) <----> SO2(g) + Cl2(g) Kp = 2.91 103 at 298 K

In a reaction at equilibrium, the partial pressure of SO2 is 132 torr and that of Cl2 is 304 torr. What is the partial pressure of SO2Cl2 in this mixture?

The answer is 0.0181 torr.
why is the answer such a small number?! i keep getting numbers closer to 9?

Expert Solution

SO2Cl2(g) <----> SO2(g) + Cl2(g) Kp = 2.91x10³

Kp = [P_SO2][p_CL2]/p_SOCL2

P = 132*304/760*2.91*10³ = 0.0181 torr

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