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Methanol (ch4o) is converted to bromomethane (ch3br) as follows: ch4o + hbr → ch3br + h2o if 12
Methanol (ch4o) is converted to bromomethane (ch3br) as follows: ch4o + hbr → ch3br + h2o if 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess hbr, what is the percentage yield
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