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Annual sales of bottled water in the country in the period 1993 - 2003 could be approximated by the function R(t)=10t∗2+100t+2400R(t)=10t∗2+100t+2400 (million gallons) where t is time in years since 1990
Annual sales of bottled water in the country in the period 1993 - 2003 could be approximated by the function R(t)=10t∗2+100t+2400R(t)=10t∗2+100t+2400 (million gallons) where t is time in years since 1990. Were sales of bottled water accelerating or decelerating in 2000? How fast?
Expert Solution
Given that:
Annual sales of bottled water in the country in the period 1993−20031993−2003 could be approximated by the function;
R(t)=10t2+100t+2400R(t)=10t2+100t+2400.
The time period between 1993−20031993−2003 is 0≤t≤100≤t≤10.
Differentiate the function R(t)R(t) with respect to tt:
R′(t)=d(10t2+100t+2400)dx=20t+100+0∴R′(t)=20t+100R′(t)=d(10t2+100t+2400)dx=20t+100+0∴R′(t)=20t+100
Again differentiate R′(t)R′(t) with respect to tt:
R′′(t)=20R″(t)=20
Therefore, annual sales of bottled water is accelerating 20 million gallons per year20 million gallons per year in 20002000
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