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Suppose you deposit $1,000 at the end of each quarter for 5 years at an interest rate of 10% compounded monthly
Suppose you deposit $1,000 at the end of each quarter for 5 years at an interest rate of 10% compounded monthly. What equal end-of-year deposit over 5 years would accumulate the same amount at the end of 5 years under the same interest compounding? Quarters 0 1 2 3 4 5 6 7 $ 9 10 11 12 13 14 15 16 17 18 19 20 TIT ITT $1,000 Years 2 A ?
Expert Solution
In order to make this calculation, we shall use the concept of present worth. We will calculate A such that the Present Worth from both these stream of cash flows are equal.
Let us first calculate the present worth of quarterly deposits of $1000 for 5 years, or 20 time periods. Now, the yearly interest rate is 10%, so we can take the quarterly interest rate as (10%/4)= 2.5%.
Present Worth = 1000/1.025 + 1000/1.0252 + 1000/1.0253 + ...... + 1000/1.02520 = (1000) × (1.02520 - 1)/(0.025 × 1.02520), which is the formula for addition in Geometric Progression.
Hence, present worth = 1000 × (1.6386 - 1)/(0.025 × 1.6386) = $15589.16
Now, let us calculate the present worth of the yearly deposits for 5 years at an annual interest rate of 10%.
Present worth = A/1.10 + A/1.102 + ... A/1.105 = $A × (1.105 - 1)/(0.10 × 1.105) = $A × (1.6105 - 1)/(1.6105 × 0.10) = 3.7908 × $A.
Hence, equating the two present worths, we have,
3.7908 × A = $15589.16 => A = $15589.16/3.7908 = $4112.37
Hence, the required amount A = $4112.37
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