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Homework answers / question archive / Consider a woman who is heterozygous for two traits: M+/M- for Maple Syrup Urine Disease on chromosome 19 and H+/H- for hemophilia on the X chromosome
Consider a woman who is heterozygous for two traits: M+/M- for Maple Syrup Urine Disease on chromosome 19 and H+/H- for hemophilia on the X chromosome.
Which of the following gamete genotype(s) should this woman expect to produce?
1. M- H+
2. M+ M-
3. M+ H+
4. H+ H+
- A. 1, 2 and 3
- B. 1 and 3
- C. 2 and 4
- D. 4 only
- E. All of 1, 2, 3 and 4 are correct.