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I need help answering part d) of this question from my textbook
I need help answering part d) of this question from my textbook...
Suppose a school has three periods (called 1, 2, and 3) during which a class can be scheduled. For each class, there are three variables. For example, for class A, there are XA1, XA2, XA3. Setting XA2 = 1 represents scheduling class A during period 2.
a) Give a Boolean expression that evaluates to 1 if and only if A is scheduled in at least one of the three periods.
answer: (XA1 + XA2 + XA3)
b) Give a Boolean expression that evaluates to 1 if and only if A is not scheduled in more than one period.
answer: (XA1XA2)(XA1XA3)(XA2XA3)
c) Give a Boolean expression that evaluates to 1 if and only if A and B are not scheduled in the same period.
answer: (XA1XB1)(XA2XB2)(XA3XB3)
d) The final Boolean expression representing the entire scheduling problem will be a product of many terms. If there are n classes and m pairs of classes that can not be scheduled at the same time, then how many terms will be in the entire Boolean expression?
I'm thinking like 2n + 2m but that seems off...
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