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Question 3 (7 points) A plane's velocity changes from 700 km/h [E40N] to 850 km/h [N20 W]
Question 3 (7 points) A plane's velocity changes from 700 km/h [E40N] to 850 km/h [N20 W]. a) Find the change in velocity, A V , in km/h. You must use the trigonometric method (sine law & cosine law). Include a fully labelled vector diagram showing the vector subtraction. [5 marks] b) If the change took 40 seconds, calculate the average acceleration during that time in m/s2. [2 marks]
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B 9/my 5 8 = in Iyo' Vi Fro with 20 Pro W S Anole setween 4, and 4, = 0= 50+ 20= 70 AB represents the difference of velocities ( v2- v. ) Herce using the formula in 40 AB AB = OA 2 + OB - 20 A . OB X COSQ (410 ) 2 = ( 720 ) 2 + (850 ) - 2X 710 x 850 x COS 70 ( 40 ) 2 = 805496 . 029 4 AU = 805 4 96 . 02 9 4 All = 897. 49ukm/s or 897 . 494X 5 = 249. 303 18 m/s (b) At = 40s so averoute acceleration during this time is a = All - 249.30] 16:2325 41 / 5 2 At
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