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Homework answers / question archive / Use the data below to answer each of the following questions: 192 228 186 199 238 217 213 234 264 187 214 115 238 246 Min: Q1: Median: Q3: Max: IQR:
Use the data below to answer each of the following questions:
192 228 186 199 238 217 213 234 264 187 214 115 238 246
Min:
Q1:
Median:
Q3:
Max:
IQR:
Step-by-step explanation
Given data is,
192 , 228 , 186 , 199 , 238 , 217 , 213 , 234 , 264 , 187 , 214 , 115 , 238 , 246
We arrange the data in ascending order and give observation numbers (rankings)
Rank (Observation number ) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 |
Observation | 115 | 186 | 187 | 192 | 199 | 213 | 214 | 217 | 228 | 234 | 238 | 238 | 246 | 264 |
From the data we observe that,
We know that,
The 1st quartile is the median of the lower half data
That is,
The 1st quartile is the median of 1st 7 Observations
Rank (Observation number ) | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Observation | 115 | 186 | 187 | 192 | 199 | 213 | 214 |
By the definition,
Q1?=Medianoflowerhalfdata=(27+1?)thobservation?Q1?=4thobservation?Q1?=192
In this case we can see that, n = 14
Median=2(2n?)thobservation+(2n?+1)thobservation??Median=2(214?)thobservation+(214?+1)thobservation??Median=27thobservation+8thobservation??Median=2214+217??Median=215.5
We know that,
The 2nd quartile is the median of the upper half data
That is,
The 2nd quartile is the median of 2nd 7 Observations
Rank (Observation number ) | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Observation | 217 | 228 | 234 | 238 | 238 | 246 | 264 |
By the definition,
Q3?=MedianofUpperhalfdata=(27+1?)thobservation?Q3?=4thobservation?Q3?=238
We know that,
IQR=Q3?−Q1??IQR=238−192?IQR=46