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I need help adding easy, medium, and difficult options to each of the mathematical equations to allow an option for each of the four options

Computer Science

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I need help adding easy, medium, and difficult options to each of the mathematical equations to allow an option for each of the four options. I also need to add a data base for how many correct and incorrect responses a user gets right or wrong. Do i add that into each separate equation?

 

#include <stdio.h>

#include <stdlib.h>

 

 

void Addition() {

int answer;

printf("36 + 12 = ?");

 

scanf_s(" %d", &answer);

 

 

if (answer == 48)

 

{

 

printf("nYou are correct");

 

}

 

else

 

{

 

printf("nIncorrect");

 

}

}

 

void Subtraction() {

int answer;

printf("8 - 4 = ?");

 

scanf_s(" %d", &answer);

 

 

if (answer == 4)

 

{

 

printf("nYou are correct");

 

}

 

else

 

{

 

printf("nIncorrect");

 

}

 

}

 

void Multiplication() {

int answer;

printf("4 * 4 = ?");

 

scanf_s(" %d", &answer);

 

 

if (answer == 16)

 

{

 

printf("nYou are correct");

 

}

 

else

 

{

 

printf("nIncorrect");

 

}

}

 

void Division() {

int answer;

printf("4 / 14 = ?");

 

scanf_s(" %d", &answer);

 

 

if (answer == 0)

 

{

 

printf("nYou are correct");

 

}

 

else

 

{

 

printf("nIncorrect");

 

}

}

 

void menu() {

 

printf("nMath Practice Menunn");

 

printf("1.Additionn2.Subtractionn3.Multiplicationn4.Divisionn5.Exit.");

 

printf("nSelect an option:");

 

}

 

 

void main()

 

{

 

int answer;

 

int option;

 

 

menu();

scanf_s("%d", &option);

 

 

while (option)

 

{

 

switch (option)

 

{

 

case 1:

 

Addition();

 

break;

 

 

case 2:

 

Subtraction();

break;

 

 

case 3:

 

Multiplication();

break;

 

 

case 4:

Division();

 

break;

 

 

case 5:

 

printf("Thank you, goodbyen");

exit(0);

break;

 

}

 

 

menu();

 

scanf_s("%d", &option);

 

}

 

 

 

return;

 

 

}