Trusted by Students Everywhere
Why Choose Us?
0% AI Guarantee
Human-written only.
24/7 Support
Anytime, anywhere.
Plagiarism Free
100% Original.
Expert Tutors
Masters & PhDs.
100% Confidential
Your privacy matters.
On-Time Delivery
Never miss a deadline.
The oxidation state of ##Cr## in chromate ion, ##CrO_4^(2-)##, is ##VI^+##
The oxidation state of ##Cr## in chromate ion, ##CrO_4^(2-)##, is ##VI^+##.
As far as anyone knows, the charge in chromate is localized on the oxygen (i.e ##(O=)_2Cr(-O^-)_2##). Chromic acid, ##H_2CrO_4## (or ##(O=)_2Cr(-OH)_2##), is the precursor; this is a potent oxidant. In each case, the metal oxidation state (##VI^+##) is clear. Note that in this formal representation, the charge on chromium is neutral. The negative charge is borne by the 2 singly bound oxygen atoms.
Expert Solution
For detailed step-by-step solution, place custom order now.
Need this Answer?
This solution is not in the archive yet. Hire an expert to solve it for you.
Get a Quote





