The mass of tin deposited is 1

The mass of tin deposited is 1.1 g.

The steps involved are: 1. Write the balanced equation. 2. Use conversion factors to convert mass of Ag → moles of Ag → moles of Sn → mass of Sn

Step 1

The balanced equation for a galvanic cell is

2 × [Ag? + e? → Ag]; ##E°## = +0.80 V 1 ×[Sn →Sn²? + 2e?]; ##E°## = +0.14 V

2Ag? + Sn → 2Ag + Sn²?; ##E°## = +0.94 V

This equation tells you that, when you force electricity between two cells in series, the moles of tin deposited are twice the moles of silver.

Step 2

Mass of Sn = 2.0 g g Ag × ##(1"mol Ag")/(107.9"g Ag") × (1"mol Sn")/(2"mol Ag") × (118.7"g Sn")/(1"mol Sn")## = 1.1 g Sn (2 significant figures)