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Nancy has a project with a $17000 first cost that returns $7000 per year over its 13-year life
Nancy has a project with a $17000 first cost that returns $7000 per year over its 13-year life. There will be a $3000 salvage value at the end of the 13-years. If Nancy uses a MARR of 14%, what is the annual worth of the project?
Expert Solution
Computation of Annual Worth of the Project:
Annual Worth = -P(A/P, i, n) + A + F(A/F, i, n)
= -17,000(A/P, 14%, 13) + 7000 + 3,000(A/F, 14%, 13)
= -17,000(0.171164) + 7,000 + 3,000(0.03116)
= -2909.78 + 7000 + 93.49
Annual Worth = $4,183.71
Workings:
(A/P, 14%, 13) = [(i*(1+i)^n)/((1+i)^n - 1)] = [(14%*(1+14%)^13)/((1+14%)^13 - 1)] = 0.171164
(A/F, 14%, 13) = i/(1+i)^n - 1 = 14% / (1+14%)^13 - 1 = 0.03116
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