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A beetle with a striped carapace is crossed with one having striped wings, producing normal looking (no stripes on the carapace or wings) progeny
A beetle with a striped carapace is crossed with one having striped wings, producing normal looking (no stripes on the carapace or wings) progeny. If two of these normal looking progeny mate with each other, what fraction of their progeny are expected to have striped carapaces and striped wings? (The genes conferring stripes or no stripes on carapace and on wings each have two alleles and are on different chromosomes).
A. 1/2
B. 3/8
C. 1/4
D. 1/16
E. There is insufficient information to make a prediction
Expert Solution
Answer:
D). 1/16
Explanation:
No stripes on the carapace = C
Stripes on the carapace = c
No stripes on the wing = W
Stripes on the wing = w
Striped carapace (ccWW) x striped wings (CCww) ----- Parents
CcWw (no stripes on the carapace or wings) --------Progeny
CcWw x CcWw ---F1 intercross
Cc x Cc = C_ (3/4) & cc (1/4)
Ww x Ww = W_ (3/4) & ww (1/4)
The fraction of their progeny are expected to have striped carapaces and striped wings = ccww = ¼ * ¼ = 1/16
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