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Power Solutions Ltd

Finance

Power Solutions Ltd. issues a $15,000,000, five-year, 4.5% bond with semi-annual interest payments. Underwriting costs, paid up front,
are $960,000. The bond sells at par.

Required:

1. How much cash does Power receive when the bond is issued?

2. What is the effective interest rate on the bond? (Round your answer to the nearest whole percentage.)

3. Prepare an amortization table using the effective-interest method of amortization. Complete the first four payments only. (Round
your effective interest rate to the nearest whole percentage and your final answers to the nearest whole dollar.)
 

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Computation of Power Receives:

Power Receives = Sales Value of Bond - Underwriting Costs

= $15,000,000-$960,000

Power Receives = $14,040,000

 

 

Computation of Effective Rate of Return using Rate Function in Excel:

=rate(nper,pmt,-pv,fv)*2

Here,

Rate = ?

Nper = 5*2 = 10 Periods

PMT = $15,000,000*4.5%/2 = $337,500

PV = $14,040,000

FV = $15,000,000

Substituting the values in formula:

=rate(10,337500,-14040000,15000000)

Rate = 6%

So, Effective Rate of Return is 6%.

 

 

Amortization Table       
Effective Interest Method    
Period Cash Interest  Interest Expenses D or P Amortization Ending Balance
Op. Balance Paid       
1 $337,500  421200 $83,700  $14,123,700 
2 $337,500  $423,711  $86,211  $14,209,911 
3 $337,500  $426,297  $88,797  $14,298,708 
4 $337,500  $428,961  $91,461  $14,390,170 
Amortization Table         
Effective Interest Method      
Period Cash Interest  Interest Expenses D or P Amortization Ending Balance
Op. Balance Paid    (Cash Interest - Interest)  
1 337500 =14040000*6%/2 =D7-C7 =14040000+83700
2 337500 =14123700*6%/2 =D8-C8 =14123700+86211
3 337500 =14209911*6%/2 =D9-C9 =14209911+88797
4 337500 =14298708*6%/2 =D10-C10 =14298708+91461

 

 

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