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Homework answers / question archive / Find the fraction under the condition:- if 4 is added to both the numerator and denominator fraction will be equal to 18/10, if 6 is subtracted from the numerator and denominator fraction will become 8/5
Find the fraction under the condition:-
if 4 is added to both the numerator and denominator fraction will be equal to 18/10, if 6 is subtracted from the numerator and denominator fraction will become 8/5.
For fist case let the fraction is x/y;
than 4 is added to numerator and denominator the fraction will be equal to 18/10;
(x+4) / (y+4) = 18 / 10
(x+4) / (y+4) = 18/10;
10x +40 = 18y + 72
10x - 18y = 32
5x - 9y = 16 -------(1)
than 6 is subtracted to numerator and denominator the fraction will be equal to 8/5;
(x - 6) / (y - 6) = 8 / 5;
5x - 30 = 8y - 48
5x - 8y = -18 -------(2)
by solving equation 1 and 2 by elemination method;
5x - 9y = 16
-5x + 8y = +18 ( changing the sign od second equation)
adding both equations we get
-y = 34;
y = -34
than x= 5x - 8 * (-34) = -18
5x = -290
x = -58
x/y = -58/-34