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Five years ago the government of a Pacific Island state launched an extensive propaganda campaign toward curbing the country's population growth

Math Aug 04, 2020

Five years ago the government of a Pacific Island state launched an extensive propaganda campaign toward curbing the country's population growth. According to the Census Department, the population (measured in thousands of people) for the following 4 years was:  P(t) = -1/3 t3 + 64t + 300  where t = 0 corresponds to the beginning of the campaign. Find the rate of change of the population at the end of years 1, 2, 3, and 4. Does it appear that the campaign is working?

Expert Solution

The given population function is P(t) = (-1/3)t3+ 64t+ 300 

so rate of change population can be determined by differentiating the function with respect to t.

initially at t = 0 the population is 300.

now differentiating ,

P'(t) = (-1/3) 3 t2 + 64 ( d(xn) / dx = n xn-1 and d(c) / dx = 0 where c is constant)

P'(t) = -t2 + 64 ;

for t = 1 ;

rate of change = P'(1) = -(1)2 + 64;

= 63;

for t = 2 ;

rate of change = P'(2) = -(2)2 + 64;

= 60;

for t = 3 ;

rate of change = P'(3) = -(3)2 + 64;

= 55;

for t = 4 ;

rate of change = P'(4) = -(4)2 + 64;

= 48;

 

 

Yes, this can be clearly seen the rate of change of population is decreasing so that population is also decreasing, hence this campaign

is a successful propaganda towards curbing the population growth

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