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Find an equation of the plane tangent to the following surface at the given point

Math Jan 25, 2021

Find an equation of the plane tangent to the following surface at the given point. 7xy +yz +4xz ? 48 = 0; (2,2,2) The equation of the tangent plane at (2,2,2) is = 0.Find an equation of the plane tangent to the following surface at the given point. yze^xz + 7 = 0; (0, - 7,1) An equation of the tangent plane at (0, - 7,1) is = 0. Find an equation of the plane tangent to the following surface at the given point. z = 4 - 4x^2 - 2y^2; (2,3,-30) z = Find an equation for the plane that is tangent to the surface z = In (x^2 + y^3) at the point P(0,1,0). The equation of the plane is = 0.

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