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Homework answers / question archive / 2) The general formula for P(A U B U C) is P(A) + P(B) + P(C) - P(A  B) - P(A  C) - P(B  C) + P(A  B  C)

2) The general formula for P(A U B U C) is P(A) + P(B) + P(C) - P(A  B) - P(A  C) - P(B  C) + P(A  B  C)

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2) The general formula for P(A U B U C) is P(A) + P(B) + P(C) - P(A \cap B) - P(A \cap C) - P(B \cap C) + P(A \cap B \cap C). Using this formula prove the following:

If A, B, and C are independent events then P(A U B U C) = P(A)+P(AC)P(B) + P(AC)P(BC)P(C)

3) Using the formula for number two, suppose you have the following scenario. You play three games of roulettte (the wheel has 38 slots, numbered 00, 0, and 1 through 36. In the first game, you bet that the winning number will be a positive multiple of three. In the second game you bet that the winning number iwll be a prime number. In the third game, you bet on green (00 and 0 are the green numbers). Find (A U B U C). What does this probability represent?

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