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Consider the following TLC plate, developed in ligroin
Consider the following TLC plate, developed in ligroin. Calculate the Rf values of A,B, and C. Which compound is the most polar? How would the Rf values change if a more polar solvent (like ethyl acetate) were used? The TLC has the origin at 0cm and the solvent front at 8cm, three at the origin labled A, B, and C. The first value above A is at 6.4cm and the second above B is at 2.1 cm and the third above C is at 5.3cm.
Expert Solution
The Rf values of A,B, and C are following:
For A:
Rf = distance moved by the compound or spot / distance moved by the solvent.
Rf = 6.4 cm / 8.0 cm= 0.8O
For B:
Rf = distance moved by the compound or spot / distance moved by the solvent.
Rf = 2.1cm / 8.0 cm= 0.26
For C:
Rf = distance moved by the compound or spot / distance moved by the solvent.
Rf = 5.3cm / 8.0 cm= 0.66
Here the Rf of A is 0.8 , B 0.26 and C 0.66
The more polar a compound has the lower Rf value means it is compound B. Because Polar compound want to bond with polar silica, while non-polar compound will move fast with eleuent hence this non-polar has highest Rf value.
The Rf values becomes larger if a more polar solvent (like ethyl acetate) were used in place ligroin. Polar solvent is more proficient at eluting the compounds from the polar adsorbent hence every compound of mixture moves faster, so the distance moved by the compound is becomes larger thus each compound would have a larger Rf value .
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