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Part AWhat is the strength of the field at point 1 in (Figure 1)
Part AWhat is the strength of the field at point 1 in (Figure 1) .
Part BSelect the correct direction of the field at point 1.
| A. down | ||||
| B. up | ||||
| C. right | ||||
|
D. left Part C What is the strength of the field at point 2 in (Figure 1) . Part D Select the correct direction of the field at point 2.
|
Figure 1 of 1 0 V 0 m. 1 m. 10V 2 m 20V 3 m. 30 V 400 V 4 m
Expert Solution
we know that electric field E=V/d
A))).from graph, for point 1 V=V2-V1
=(10-0)=10V & d2-d1=2-0=2m
so E=10/2=5 V/m & it is in lft direction
B))).for point 2,,, V=v2-v1
=40-20=20 V &d2-d1=4-3=1 m
E=v/d
E=20/1=20 V/m& it is left direction
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