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Archimedes principle states that the buoyant force on a submerged body equals the weight of the fluid displaced

Physics Jan 16, 2021

Archimedes principle states that the buoyant force on a submerged body equals the weight of the fluid displaced. This fact can be combined with measured weights of the object in air and in water to determine the object's density rho_3. The resulting equation is: rho = rho_w/1 - (W_w/W_a) (1) where: rho_w = density of water = 1.00 g/cm^3 W_a = weight of object in air W_w = weight of object in water Provide an explanation of the origin of the above relationship. Recall that W_a = M_g = rho Vg. A free-body diagram suggests that its weight in water is diminished by an amount equal to the buoyant force.

Expert Solution

let the mass of body = m, volume = v, density = \rho

weight of the body in air = w_{a} = mg =\rho vg .....equation-1

according to archimedes principle buoyant force is given by

F_{B} = weight of same volume water = v = \rho_{w}vg

from the diagram weight in water is given by

w_{w}=mg-F_{B}

=> w_{w}=mg-\rho _{w}vg   .....equation-2

from equatons 1 & 2

w_{a}-w_{w}=mg-(mg-\rho _{w}vg)

\rho _{w}vg

=>   \frac{w_{a}-w_{w}}{w_{a}}=\frac{\rho _{w}vg}{\rho vg}

=> 1-\frac{w_{w}}{w_{a}}=\frac{\rho _{w}}{\rho }

=> \rho =\frac{\rho _{w}}{1-\frac{\rho _{w}}{\rho }}

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