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A proton follows the path shown in (Figure 1)
A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.4?106m/s .
What is the proton's speed as it passes through point P?
Expert Solution
Apply Energy consrvation,
K2 + U2 = K1 + U1
0.5*m*v^2 + k*q1*q2/r2 = 0.5*m*vo^2 + k*q1*q2/r1
0.5*m*v^2 = 0.5*m*vo^2 + k*q1*q2*(1/r1 - 1/r2)
v^2 = vo^2 + (2*k*q1*q2/m)(1/r1 - 1/r2)
= (2.4*10^6)^2 + (-2*9*10^9*10*10^-9*1.6*10^-19/1.67*10^-27)*(1/3-1/4)*10^-3
= 5.76*10^12 - 1.43*10^12
= 4.33*10^12
v = 2.08*10^6 m/s
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