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Homework answers / question archive / Using the Standard Normal Table (ZTable
Using the Standard Normal Table (ZTable.pdf) from the online lectures this week, what is the area under the standard normal curve: • To the left of a z-score of 1.25. • To the right of a z-score of 1.25. • Between the Z-scores -0.25 and 0.55.
Standard Normal Probabilities Table entry for is the area under the standard normal curve to the left of 8078 2 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0. 9 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 .00 .01 .02 .03 04 05 06 07 08 .09 5000 5040 SOBO S12051605199523952795319 350 5398 548 5478 5517 5557 5596 5636 5675 5714 5793 5910 5948 5987 6026 6064 6103 5141 .6179 6217 6255 .6293 6331 .6368 6406 6443 6480 5517 6554 65916628 .6664 6700 6736 6772 6808 .6854 .6879 6915 .6950 6985 7019 7054 7098 7123 7157 7190 7224 7257 7291 7324 .7357 7389 74227454 7486 7517 7549 7580 2611 7642 7673 7704 7734 7764 7794 7823 .7852 7881 7910 7939 7967 79958023 8051 8106 8133 81598186 8212 8238 8264 82898315 8340 8365 8389 8413 .8438 8461 8485 850B8531 .8554 8577 8599 .8621 86438665 8586 8708 872987498770 8790 8810 BRBO 88498869 8888 8907 8925 8944 .896289808997 .9015 9032 90499066 9082 9099 9115 91319147 9162 9177 91929207 9222 .9236 9251 92659279 9292 9306 9319 9332 .93459357 93709382 .9394 9406 9418 9429 9441 .9452 .9474 9484 94959505 9515 9525 9535 9545 9554 95649573.9582959195999608 9516 9625 9633 9641 96499656 9664 9671 9678 9686 96939699 9706 97139719 9726 9732 9738 97449750 9756 9761 .9767 9772 9778 9783 9 788 9793 9798 9803 9808 9812 .9817 9821 9826 9830 9834 9838 9842 9846 9850 9854 9857 9861 9864 986898719875 9878 9881 9884 9887 .9890 9893 9896 9898 9901 99049906 9909 9911 9913 .9916 .9918 .9920 .99229925 9927 99299931 .9932 9934 .9936 9938 .9940 9941994399459946 9948 99499951 .9952 9953 .9955 .9956 9957 9959 .9960 .9961 .9962 9963 .9964 .9965 9966 9967 9968 99699970 .9971 99729973 .9974 9974 9975 9976 9977 9977 9978997999799980 .9981 .9981 .9982 .99829983 9984 99849985 99859986 .9986 .998799879987 .9988 9988.99899989998999909990 .9990 .9991 9991 .9991 9992 .9992 .9992 .9992 9993 .9993 .99939993 9994 9994 9994 9994 .9994 .9995 9995 .9995 99999999999999969996 9996 9996 9996 9996 .9997 999799979997 99979997 .9997 999799979997 -9998 1.9 92 2.0 2.2 2.4 2.5 26 2.7 2.8 3.0 3.1 3.2 3.4
from Standard Normal probability table,
z row 1.2 and z column 0.05 the value is 0.8944
Hence P( Z<1.25) = 0.8944
from Standard Normal probability table,
z row 1.2 and z column 0.05 the value is 0.8944
Hence P( Z>1.25) = 1 - P( Z<1.25) =1 - 0.8944 = 0.1056
from Standard Normal probability table,
z row 0.2 and z column 0.05 the value is 0.5987
z row 0.5 and z column 0.05 the value is 0.7088
Hence P( -0.25 < Z< 0.55) = P(0.55) - P(Z<-0.25) =0.7088 - (1-0.5987) = 0.3075
