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Homework answers / question archive / A box contains blue chips and red chips
A box contains blue chips and red chips. A person selects two chips without replacement. If the probability of selecting a blue chip and then a red chip is 12/45 and the probability of selecting a blue chip on the first draw is 6/10, find the probability of selecting the red chip on the second draw, given that the first chip selected was a blue chip? Answer with one of these: 4/9 or 8/9 or 3/5 or 3/10
Answer: 4/9
Step-by-step explanation
P(A|B) = P(A AND B) / P(B)
P(red second draw | blue first draw) = P(red second draw AND blue first draw) / P(blue first draw)
P(red second draw | blue first draw) = (12/45) / (6/10)
= (12/45)*(10/6)
= 120/270
= 12/27
= 4/9
