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Homework answers / question archive / Find the equivalent resistance between points A and B in the drawing (R1 = 5
Find the equivalent resistance between points A and B in the drawing (R1 = 5.00 Ω, R2 = 7.00Ω)
6.00 2 1.00 2 4.00 3.00 2 3.00 2
1 ohm,R2 and 3 ohm are in series,then net resistance of these are Rs = 1+7+3 = 11 ohm
this Rs is parallel to 3 ohm
then net resistance of these are Rp = (Rs*3)/(Rs+3) = (11*3)/(11+3) = 2.35 ohm
net resisatnce of Rp and 6 ohm is Rx = 6+2.35 = 8.35 ohm
then net resistance of 8.5 ohm and 4 ohm is Ry = (8.5*4)/(8.5+4) = 2.72 ohm
So net resistance of R1 and 2.72 ohm is Rnet = 5+2.72 = 7.72 ohm
