Trusted by Students Everywhere
Why Choose Us?
0% AI Guarantee
Human-written only.
24/7 Support
Anytime, anywhere.
Plagiarism Free
100% Original.
Expert Tutors
Masters & PhDs.
100% Confidential
Your privacy matters.
On-Time Delivery
Never miss a deadline.
##" so "x= 0
##" so "x= 0.8bar3 = 5/6##
To format this question type you write: 0.8bar3
But you use the hash key just before 0.8bar3 and also at the end. So you end up with
##" "0.8bar3##
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Let ##x=0.8bar3##
Then ##10x = 8.bar3##
So ##(10x-x)=" " 8.3333bar3## ##" "underline(0.8333bar3-## Subtracting ##" "7.5##
##" "9x = 7.5##
Multiply both sides by 10
##" "90x=75##
Divide both sides by 90
##" "x=75/90 = 5/6##
##" so "x= 0.8bar3 = 5/6##
Expert Solution
For detailed step-by-step solution, place custom order now.
Need this Answer?
This solution is not in the archive yet. Hire an expert to solve it for you.
Get a Quote





