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At t =0s, the current in the circuit in the figure is I0
At t =0s, the current in the circuit in the figure is I0. At what time is the current 12I0?
Expert Solution
here
I(t) = I0 * e^(-t /T)
I(t) = I0 * e^(- t*R/L) = 0.5 * I0
e^(- t*R /L) = 0.5
t = L * ln2 /R
t = (75 * 10^-3 * ln(2)) / 300
t = 1.73 * 10^-4 sec
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