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XYZ company is planning to build a hotel, the company has three alternatives to build large, medium, or small hotel

Accounting Nov 12, 2020

XYZ company is planning to build a hotel, the company has three alternatives to build large, medium, or small hotel. The company decided that the profitability will be affected the level of the future demand. The company considered only two demand possibilities, strong or weak demand. The company expects that S8 million net profit will be generated if company built a small hotel and demand turns out to be strong, if the demand turns out to be weak the profit is expected to be 7 million. A medium hotel will result in a net profit of 14 million in a strong demand, in weak demand it is expected to generate 5 million. A large hotel will result in 20 million profit in strong demand but a net loss of 9 million will occur if the demand is weak. Suppose that the XYZ management believe that the probability of strong demand is (-8) and the probability of weak demand is (2). Find the expected value of each alternative? Which alternative will they choose? 2) Suppose that you enter a drawing by obtaining one of 20 tickets that have been distributed. What is the probability of your winning the drawing Given the following distribution: Male or Outcome Random Variable Probability A + 3 3 3 D What is the expected value ? What is the variance? show your work The number of defects that occur per unit of product follows a Poisson distribution (binomial) with a mean of 4 defects per unit. What is the standard deviation of this distribution? In a given office, the color printer breaks down with a probability of 20% in any month. A binomial process is assumed for a period of 10 months. What is the probability that the printer breaks down exactly 2 times?

Expert Solution

Value of each alternative when P(Strong) = 0.8 and P(Weak) = 0.2

Small hotel = 7.8

Medium hotel = 12.2

Large hotel = 14.2

They will choose to build large hotel.

2). P( Winning the drawing ) = 1/20 = 0.05

3) value = sumproduct ( value,probability)

= 2

Variance = sumproduct ( (value - mean)^2, probability)

= 1.3

4) std dev of Poisson distribution = sort ( mean )

STD DEV = sort (4) = 2

5) probability of printer breaking down exactly twice is 0.3020

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