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Consider the collection of point charges arranged along a line shown in the figure above (note: drawing is not to scale!)
Consider the collection of point charges arranged along a line shown in the figure above (note: drawing is not to scale!). Point Pis in free space to the right of the charges. There is no charge at point P. Use 9 x 10°Nm²/C2 fork. The charges and distances, as shown in the figure, have values of: 4A = 7.00 AC, 4 = -97C, 4c = -28 C, 4 = 75.00 pc, a = 4.280 cm, b = 5.540 cm, c = 5.380 cm, d = 5.530 cm You may also find some of these distance values useful: a + b = 9.82 cm, a + b + c = 15.2 cm, a + b + c + d = 20.73 cm, b + c = 10.92 cm, b + C + d = 16.45 cm, c + d = 10.91 cm As shown in the figure, we choose the positive direction to point right (+x). Use that same sign convention for your answers to the questions below (e.g. positive vector means the vector points to the right). a) What is the net electric force on charge 4? N b) What is the net electric field at point P? N/C c) If you place a negative test charge at point P, the force on the test charge points: O In the negative x direction (to the left on the page) Into the page O In the positive x direction (to the right on the page) Towards the top of the page O Out of the page Towards the bottom of the page d) Find the electric potential at point P. Volts e) How much energy would be required to bring a charge of q = 5 xC from infinitely far away to point P? Now consider the same arrangement of the same charges as above, but add a solid aluminum block to the left of the charges, as shown below. Point S is inside of the aluminum block, a distance x = 4.480 cm to the left of charge A. 5 c X 9A 26 7c ?? f) What is the net electric field at point ? IN/c x + a = 8.76 cm, x + a + b = 14.3 cm, a + b + C + x = 19.68 cm
Expert Solution
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Ans 1:
-539.04 N
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1.98*10^8 N/C
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in the negative x direction
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9.71*10^6 V
what is the charge for d ?
qD = 75.00 ?C
How much energy would be required to bring a charge of q = 5 ?C from infinitely far away to point P?
Please view explanation and answer below.
990.14 J
just put - infront of that value
for e)
990.13 J
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