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In a given sample studying corona virus infectiousness, 13% of infected people were youth and 66% were elderly

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In a given sample studying corona virus infectiousness, 13% of infected people were youth and 66% were elderly. Moreover, of not infected people, 46% were adults and 11% were elderly. If you know that 73% of the sample received negative test result (i.e. not infected), and events are mutually exclusive and collectively exhaustive; Assume that infected and adult are two independent events, find the probability that a person is infected or adult? [5 points) b. Find the probability that a person is infected if he/she is an youth?

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Question 2) a) Percentage of negative sample (not infected) = 73% = 0.73

Percentage of people with positive sample (are infected) = 1-73% = 27% = 0.27

Percentage of people who are adults =

= Percentage of infected adults + Percentage of not infected adults

= (1-0.66-0.13)*0.27 + 0.46*0.73

= 0.3925

Percentage of people who are infected or adult =

= Percentage of people who are infected + Percentage of people who are adult - Percentage of people who are adult and infected

= 0.27 + 0.3925 - (0.27*0.21)

= 0.6058

Probability of people who are infected or adult are 0.6058.

b)Percentageof people who are youth =

= 0.27*0.13 + 0.73*(1-0.46-0.11)

= 0.27*0.13 + 0.73*0.43

= 0.349

Probability that a person is infected if he/she is a youth =

= Probability that a person is infected and is a youth / Probability that a person is a youth

= 0.13/0.349

= 0.3725.